2015年2月11日 · Maybe someone will help you, but they should first consider the fact that you've asked 18 questions and accepted none of them and in fact you have never even upvoted.

2023年3月29日 · But how can i proof that KerT ∩ ImT = {0} K e r T ∩ I m T = {0} or disprove it

2020年2月18日 · Find a base for Im T Im T. I know that the columns of [T]B [T] B are the coordinates vectors of the vectors which span Im T Im T, but I don't understand how to find a …

2019年6月15日 · I managed to find the basis and the dimension for ImT I m T pretty easily, however how do I formally prove the dimension and the basis for KerT K e r T?

You may check your basis for ImT. dimImT must be 2.

Linear Tranformation that preserves Direct sum V = ImT ⊕ KerT V = I m T ⊕ K e r T

2015年11月3日 · You say "this is a well known fact for T T is a linear transformation". If you assume your idempotent transformation to be linear then of course it should hold for it, too, …

Explain why the columns of an n × n n × n matrix A A are linearly independent when A A is invertible. The proof that I thought of was: If A A is invertible, then A ∼ I A ∼ I (A A is row …

You really need either to use cos(x) = exp (ix) + exp (− ix) 2 or cos(x) = ℜ(exp(ix)) so that we work with exp(ix) over the upper half-plane. cos(ix) blows up exponentially as the imaginary part of x …

Then usually at this point we would solve the differential equation for all , and use the known information at the origin to infer the information at infinity. Not so easy here because the …