2012年12月21日 · If you want to stick with the same sort of loop then this will work: Option Explicit Sub selectColumns() Dim topSelection As Integer Dim endSelection As Integer topSelection = 2 endSelection = 10 Dim columnSelected As Integer columnSelected = 1 Do With Excel.ThisWorkbook.ActiveSheet .Range(.Cells(columnSelected, columnSelected), …

2018年4月2日 · In VBA this is <> (Not equal to) operator. The result becomes true if expression1 <> expression2.

Why and how is the hash-sign (number-sign or pound-sign) used in this VBA statement. Hot Network Questions ...

2017年7月14日 · Microsoft Excel's VBA: If Statements running incorrectly, Always Run. 0.

It's the bitness of the execution context (VBA/CLR) which is important here and the bitness of the loaded VBA/CLR depends upon the bitness of the host process. Between 32/64-bit calls, most notable things that go wrong are using long or int (constant-sized in CLR) instead of IntPtr (dynamic sized based on bitness) for "pointer types".

What I need to do is be able to execute this file using VBA's shell() command. How do I have to format the file path to tell Shell() that there is an argument that it needs to call along with running the .exe. What I've read/tried (with no avail) is below with the results to the right.

2017年8月16日 · You can't use If statement in condition in another If statement. One solution is to use nested If's, for more info look here.

2015年5月21日 · But in For loop in VBA, Step value can not be changed dynamically. For example: Dim i As Integer For i = 1 To 10 Step i Debug.Print i Next i Here, before starting iteration Step is equal to the value of i that is the default value i.e. 0. So i …

2015年10月13日 · VBA stands for Visual Basic for Applications and so is the small "for applications" scripting brother of VB. VBA is indeed available in Excel, but also in the other office applications. With VB, one can create a stand-alone windows application, which is …

2015年2月18日 · Alternative using VBA's Filter function. As an innovative alternative to @schlebe 's recent answer, I tried to use the Filter function integrated in VBA, which allows to filter out a given search string setting the third argument to False. All "negative" search strings (e.g. A, B, C) are defined in an array.